Cody left City Y for City X at 07 37. Gillian left City Y for City C at the same time. At 10 37, they were 504 km apart. Both maintained a constant speed and reached their destination at the same time at 12 17.
- Find the distance between Cities A and C.
- If Gillian was 59 the speed of Cody, find Cody's speed.
(a)
Time taken for Cody and Gillian to travel 07 37 to 10 37 = 3 h
Time taken for Cody and Gillian to travel 07 37 to 12 17 = 4 h 40 min = 4
4060 h = 4
23 h
Distance travelled by Cody and Gillian in 1 hour
= 504 ÷ 3
= 168 km
Total distance
= 4
23 x 168
= 784 km
(b)
Gillian's distance : Cody's distance
5 : 9
Gillian's speed : Cody's speed
5 : 9
14 u = 168 km
1 u = 168 ÷ 14 = 12 km
Cody's speed
= 9 u
= 9 x 12
= 108 km/h
Answer(s): (a) 784 km; (b) 108km/h