Paul left City X for City W at 09 37. Natalie left City X for City C at the same time. At 11 37, they were 312 km apart. Both maintained a constant speed and reached their destination at the same time at 14 12.
- Find the distance between Cities A and C.
- If Natalie was 67 the speed of Paul, find Paul's speed.
(a)
Time taken for Paul and Natalie to travel 09 37 to 11 37 = 2 h
Time taken for Paul and Natalie to travel 09 37 to 14 12 = 4 h 35 min = 4
3560 h = 4
712 h
Distance travelled by Paul and Natalie in 1 hour
= 312 ÷ 2
= 156 km
Total distance
= 4
712 x 156
= 715 km
(b)
Natalie's distance : Paul's distance
6 : 7
Natalie's speed : Paul's speed
6 : 7
13 u = 156 km
1 u = 156 ÷ 13 = 12 km
Paul's speed
= 7 u
= 7 x 12
= 84 km/h
Answer(s): (a) 715 km; (b) 84km/h