Michael left City Z for City Y at 08 50. Gem left City Z for City C at the same time. At 10 50, they were 320 km apart. Both maintained a constant speed and reached their destination at the same time at 13 44.
- Find the distance between Cities A and C.
- If Gem was 79 the speed of Michael, find Michael's speed.
(a)
Time taken for Michael and Gem to travel 08 50 to 10 50 = 2 h
Time taken for Michael and Gem to travel 08 50 to 13 44 = 4 h 54 min = 4
5460 h = 4
910 h
Distance travelled by Michael and Gem in 1 hour
= 320 ÷ 2
= 160 km
Total distance
= 4
910 x 160
= 784 km
(b)
Gem's distance : Michael's distance
7 : 9
Gem's speed : Michael's speed
7 : 9
16 u = 160 km
1 u = 160 ÷ 16 = 10 km
Michael's speed
= 9 u
= 9 x 10
= 90 km/h
Answer(s): (a) 784 km; (b) 90km/h