Justin left City Z for City Y at 06 36. Fanny left City Z for City C at the same time. At 10 36, they were 672 km apart. Both maintained a constant speed and reached their destination at the same time at 13 31.
- Find the distance between Cities A and C.
- If Fanny was 57 the speed of Justin, find Justin's speed.
(a)
Time taken for Justin and Fanny to travel 06 36 to 10 36 = 4 h
Time taken for Justin and Fanny to travel 06 36 to 13 31 = 6 h 55 min = 6
5560 h = 6
1112 h
Distance travelled by Justin and Fanny in 1 hour
= 672 ÷ 4
= 168 km
Total distance
= 6
1112 x 168
= 1162 km
(b)
Fanny's distance : Justin's distance
5 : 7
Fanny's speed : Justin's speed
5 : 7
12 u = 168 km
1 u = 168 ÷ 12 = 14 km
Justin's speed
= 7 u
= 7 x 14
= 98 km/h
Answer(s): (a) 1162 km; (b) 98km/h