Eric left City Y for City X at 08 41. Winnie left City Y for City C at the same time. At 12 41, they were 780 km apart. Both maintained a constant speed and reached their destination at the same time at 14 17.
- Find the distance between Cities A and C.
- If Winnie was 78 the speed of Eric, find Eric's speed.
(a)
Time taken for Eric and Winnie to travel 08 41 to 12 41 = 4 h
Time taken for Eric and Winnie to travel 08 41 to 14 17 = 5 h 36 min = 5
3660 h = 5
35 h
Distance travelled by Eric and Winnie in 1 hour
= 780 ÷ 4
= 195 km
Total distance
= 5
35 x 195
= 1092 km
(b)
Winnie's distance : Eric's distance
7 : 8
Winnie's speed : Eric's speed
7 : 8
15 u = 195 km
1 u = 195 ÷ 15 = 13 km
Eric's speed
= 8 u
= 8 x 13
= 104 km/h
Answer(s): (a) 1092 km; (b) 104km/h