Warren left City X for City W at 08 42. Xylia left City X for City C at the same time. At 12 42, they were 672 km apart. Both maintained a constant speed and reached their destination at the same time at 14 32.
- Find the distance between Cities A and C.
- If Xylia was 59 the speed of Warren, find Warren's speed.
(a)
Time taken for Warren and Xylia to travel 08 42 to 12 42 = 4 h
Time taken for Warren and Xylia to travel 08 42 to 14 32 = 5 h 50 min = 5
5060 h = 5
56 h
Distance travelled by Warren and Xylia in 1 hour
= 672 ÷ 4
= 168 km
Total distance
= 5
56 x 168
= 980 km
(b)
Xylia's distance : Warren's distance
5 : 9
Xylia's speed : Warren's speed
5 : 9
14 u = 168 km
1 u = 168 ÷ 14 = 12 km
Warren's speed
= 9 u
= 9 x 12
= 108 km/h
Answer(s): (a) 980 km; (b) 108km/h