Wesley left City K for City J at 07 37. Fanny left City K for City C at the same time. At 10 37, they were 432 km apart. Both maintained a constant speed and reached their destination at the same time at 13 17.
- Find the distance between Cities A and C.
- If Fanny was 35 the speed of Wesley, find Wesley's speed.
(a)
Time taken for Wesley and Fanny to travel 07 37 to 10 37 = 3 h
Time taken for Wesley and Fanny to travel 07 37 to 13 17 = 5 h 40 min = 5
4060 h = 5
23 h
Distance travelled by Wesley and Fanny in 1 hour
= 432 ÷ 3
= 144 km
Total distance
= 5
23 x 144
= 816 km
(b)
Fanny's distance : Wesley's distance
3 : 5
Fanny's speed : Wesley's speed
3 : 5
8 u = 144 km
1 u = 144 ÷ 8 = 18 km
Wesley's speed
= 5 u
= 5 x 18
= 90 km/h
Answer(s): (a) 816 km; (b) 90km/h