Sam left City G for City F at 06 50. Cindy left City G for City C at the same time. At 11 50, they were 660 km apart. Both maintained a constant speed and reached their destination at the same time at 13 35.
- Find the distance between Cities A and C.
- If Cindy was 47 the speed of Sam, find Sam's speed.
(a)
Time taken for Sam and Cindy to travel 06 50 to 11 50 = 5 h
Time taken for Sam and Cindy to travel 06 50 to 13 35 = 6 h 45 min = 6
4560 h = 6
34 h
Distance travelled by Sam and Cindy in 1 hour
= 660 ÷ 5
= 132 km
Total distance
= 6
34 x 132
= 891 km
(b)
Cindy's distance : Sam's distance
4 : 7
Cindy's speed : Sam's speed
4 : 7
11 u = 132 km
1 u = 132 ÷ 11 = 12 km
Sam's speed
= 7 u
= 7 x 12
= 84 km/h
Answer(s): (a) 891 km; (b) 84km/h