Oliver left City W for City V at 08 38. Jaslyn left City W for City C at the same time. At 10 38, they were 304 km apart. Both maintained a constant speed and reached their destination at the same time at 15 23.

1. Find the distance between Cities A and C.
2. If Jaslyn was ³₅ the speed of Oliver, find Oliver's speed.

(a)
Time taken for Oliver and Jaslyn to travel 08 38 to 10 38 = 2 h
Time taken for Oliver and Jaslyn to travel 08 38 to 15 23 = 6 h 45 min = 6⁴⁵₆₀ h = 6³₄ h

Distance travelled by Oliver and Jaslyn in 1 hour
= 304 ÷ 2
= 152 km

Total distance
= 6³₄ x 152
= 1026 km

(b)
Jaslyn's distance : Oliver's distance
3 : 5

Jaslyn's speed : Oliver's speed
3 : 5

8 u = 152 km
1 u = 152 ÷ 8 = 19 km

Oliver's speed
= 5 u
= 5 x 19
= 95 km/h

Answer(s): (a) 1026 km; (b) 95km/h