Japheth left City K for City J at 08 38. Xylia left City K for City C at the same time. At 11 38, they were 528 km apart. Both maintained a constant speed and reached their destination at the same time at 14 23.

1. Find the distance between Cities A and C.
2. If Xylia was ⁷₉ the speed of Japheth, find Japheth's speed.

(a)
Time taken for Japheth and Xylia to travel 08 38 to 11 38 = 3 h
Time taken for Japheth and Xylia to travel 08 38 to 14 23 = 5 h 45 min = 5⁴⁵₆₀ h = 5³₄ h

Distance travelled by Japheth and Xylia in 1 hour
= 528 ÷ 3
= 176 km

Total distance
= 5³₄ x 176
= 1012 km

(b)
Xylia's distance : Japheth's distance
7 : 9

Xylia's speed : Japheth's speed
7 : 9

16 u = 176 km
1 u = 176 ÷ 16 = 11 km

Japheth's speed
= 9 u
= 9 x 11
= 99 km/h

Answer(s): (a) 1012 km; (b) 99km/h