Luke left City Y for City X at 08 24. Opal left City Y for City C at the same time. At 10 24, they were 330 km apart. Both maintained a constant speed and reached their destination at the same time at 15 16.
- Find the distance between Cities A and C.
- If Opal was 56 the speed of Luke, find Luke's speed.
(a)
Time taken for Luke and Opal to travel 08 24 to 10 24 = 2 h
Time taken for Luke and Opal to travel 08 24 to 15 16 = 6 h 52 min = 6
5260 h = 6
1315 h
Distance travelled by Luke and Opal in 1 hour
= 330 ÷ 2
= 165 km
Total distance
= 6
1315 x 165
= 1133 km
(b)
Opal's distance : Luke's distance
5 : 6
Opal's speed : Luke's speed
5 : 6
11 u = 165 km
1 u = 165 ÷ 11 = 15 km
Luke's speed
= 6 u
= 6 x 15
= 90 km/h
Answer(s): (a) 1133 km; (b) 90km/h