Fabian left City K for City J at 07 46. Shannon left City K for City C at the same time. At 10 46, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 14 43.
- Find the distance between Cities A and C.
- If Shannon was 45 the speed of Fabian, find Fabian's speed.
(a)
Time taken for Fabian and Shannon to travel 07 46 to 10 46 = 3 h
Time taken for Fabian and Shannon to travel 07 46 to 14 43 = 6 h 57 min = 6
5760 h = 6
1920 h
Distance travelled by Fabian and Shannon in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 6
1920 x 180
= 1251 km
(b)
Shannon's distance : Fabian's distance
4 : 5
Shannon's speed : Fabian's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Fabian's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1251 km; (b) 100km/h