Cody left City N for City M at 08 44. Barbara left City N for City C at the same time. At 11 44, they were 504 km apart. Both maintained a constant speed and reached their destination at the same time at 14 24.
- Find the distance between Cities A and C.
- If Barbara was 35 the speed of Cody, find Cody's speed.
(a)
Time taken for Cody and Barbara to travel 08 44 to 11 44 = 3 h
Time taken for Cody and Barbara to travel 08 44 to 14 24 = 5 h 40 min = 5
4060 h = 5
23 h
Distance travelled by Cody and Barbara in 1 hour
= 504 ÷ 3
= 168 km
Total distance
= 5
23 x 168
= 952 km
(b)
Barbara's distance : Cody's distance
3 : 5
Barbara's speed : Cody's speed
3 : 5
8 u = 168 km
1 u = 168 ÷ 8 = 21 km
Cody's speed
= 5 u
= 5 x 21
= 105 km/h
Answer(s): (a) 952 km; (b) 105km/h