Peter left City K for City J at 06 20. Erika left City K for City C at the same time. At 10 20, they were 840 km apart. Both maintained a constant speed and reached their destination at the same time at 13 18.
- Find the distance between Cities A and C.
- If Erika was 78 the speed of Peter, find Peter's speed.
(a)
Time taken for Peter and Erika to travel 06 20 to 10 20 = 4 h
Time taken for Peter and Erika to travel 06 20 to 13 18 = 6 h 58 min = 6
5860 h = 6
2930 h
Distance travelled by Peter and Erika in 1 hour
= 840 ÷ 4
= 210 km
Total distance
= 6
2930 x 210
= 1463 km
(b)
Erika's distance : Peter's distance
7 : 8
Erika's speed : Peter's speed
7 : 8
15 u = 210 km
1 u = 210 ÷ 15 = 14 km
Peter's speed
= 8 u
= 8 x 14
= 112 km/h
Answer(s): (a) 1463 km; (b) 112km/h