Julian left City V for City U at 08 39. Tina left City V for City C at the same time. At 12 39, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 15 25.
- Find the distance between Cities A and C.
- If Tina was 78 the speed of Julian, find Julian's speed.
(a)
Time taken for Julian and Tina to travel 08 39 to 12 39 = 4 h
Time taken for Julian and Tina to travel 08 39 to 15 25 = 6 h 46 min = 6
4660 h = 6
2330 h
Distance travelled by Julian and Tina in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 6
2330 x 180
= 1218 km
(b)
Tina's distance : Julian's distance
7 : 8
Tina's speed : Julian's speed
7 : 8
15 u = 180 km
1 u = 180 ÷ 15 = 12 km
Julian's speed
= 8 u
= 8 x 12
= 96 km/h
Answer(s): (a) 1218 km; (b) 96km/h