Henry left City K for City J at 08 47. Jaslyn left City K for City C at the same time. At 11 47, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 15 39.
- Find the distance between Cities A and C.
- If Jaslyn was 57 the speed of Henry, find Henry's speed.
(a)
Time taken for Henry and Jaslyn to travel 08 47 to 11 47 = 3 h
Time taken for Henry and Jaslyn to travel 08 47 to 15 39 = 6 h 52 min = 6
5260 h = 6
1315 h
Distance travelled by Henry and Jaslyn in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 6
1315 x 180
= 1236 km
(b)
Jaslyn's distance : Henry's distance
5 : 7
Jaslyn's speed : Henry's speed
5 : 7
12 u = 180 km
1 u = 180 ÷ 12 = 15 km
Henry's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1236 km; (b) 105km/h