Wesley left City T for City S at 08 33. Jen left City T for City C at the same time. At 13 33, they were 900 km apart. Both maintained a constant speed and reached their destination at the same time at 15 11.
- Find the distance between Cities A and C.
- If Jen was 45 the speed of Wesley, find Wesley's speed.
(a)
Time taken for Wesley and Jen to travel 08 33 to 13 33 = 5 h
Time taken for Wesley and Jen to travel 08 33 to 15 11 = 6 h 38 min = 6
3860 h = 6
1930 h
Distance travelled by Wesley and Jen in 1 hour
= 900 ÷ 5
= 180 km
Total distance
= 6
1930 x 180
= 1194 km
(b)
Jen's distance : Wesley's distance
4 : 5
Jen's speed : Wesley's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Wesley's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1194 km; (b) 100km/h