Glen left City P for City N at 06 49. Sabrina left City P for City C at the same time. At 10 49, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 12 41.
- Find the distance between Cities A and C.
- If Sabrina was 57 the speed of Glen, find Glen's speed.
(a)
Time taken for Glen and Sabrina to travel 06 49 to 10 49 = 4 h
Time taken for Glen and Sabrina to travel 06 49 to 12 41 = 5 h 52 min = 5
5260 h = 5
1315 h
Distance travelled by Glen and Sabrina in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 5
1315 x 180
= 1056 km
(b)
Sabrina's distance : Glen's distance
5 : 7
Sabrina's speed : Glen's speed
5 : 7
12 u = 180 km
1 u = 180 ÷ 12 = 15 km
Glen's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1056 km; (b) 105km/h