Tim left City C for City B at 08 50. Wendy left City C for City C at the same time. At 11 50, they were 504 km apart. Both maintained a constant speed and reached their destination at the same time at 15 20.
- Find the distance between Cities A and C.
- If Wendy was 57 the speed of Tim, find Tim's speed.
(a)
Time taken for Tim and Wendy to travel 08 50 to 11 50 = 3 h
Time taken for Tim and Wendy to travel 08 50 to 15 20 = 6 h 30 min = 6
3060 h = 6
12 h
Distance travelled by Tim and Wendy in 1 hour
= 504 ÷ 3
= 168 km
Total distance
= 6
12 x 168
= 1092 km
(b)
Wendy's distance : Tim's distance
5 : 7
Wendy's speed : Tim's speed
5 : 7
12 u = 168 km
1 u = 168 ÷ 12 = 14 km
Tim's speed
= 7 u
= 7 x 14
= 98 km/h
Answer(s): (a) 1092 km; (b) 98km/h