Luis left City C for City B at 08 45. Anna left City C for City C at the same time. At 10 45, they were 416 km apart. Both maintained a constant speed and reached their destination at the same time at 14 15.
- Find the distance between Cities A and C.
- If Anna was 67 the speed of Luis, find Luis's speed.
(a)
Time taken for Luis and Anna to travel 08 45 to 10 45 = 2 h
Time taken for Luis and Anna to travel 08 45 to 14 15 = 5 h 30 min = 5
3060 h = 5
12 h
Distance travelled by Luis and Anna in 1 hour
= 416 ÷ 2
= 208 km
Total distance
= 5
12 x 208
= 1144 km
(b)
Anna's distance : Luis's distance
6 : 7
Anna's speed : Luis's speed
6 : 7
13 u = 208 km
1 u = 208 ÷ 13 = 16 km
Luis's speed
= 7 u
= 7 x 16
= 112 km/h
Answer(s): (a) 1144 km; (b) 112km/h