Albert left City Q for City P at 08 50. Tiffany left City Q for City C at the same time. At 13 50, they were 800 km apart. Both maintained a constant speed and reached their destination at the same time at 15 20.

1. Find the distance between Cities A and C.
2. If Tiffany was ³₅ the speed of Albert, find Albert's speed.

(a)
Time taken for Albert and Tiffany to travel 08 50 to 13 50 = 5 h
Time taken for Albert and Tiffany to travel 08 50 to 15 20 = 6 h 30 min = 6³⁰₆₀ h = 6¹₂ h

Distance travelled by Albert and Tiffany in 1 hour
= 800 ÷ 5
= 160 km

Total distance
= 6¹₂ x 160
= 1040 km

(b)
Tiffany's distance : Albert's distance
3 : 5

Tiffany's speed : Albert's speed
3 : 5

8 u = 160 km
1 u = 160 ÷ 8 = 20 km

Albert's speed
= 5 u
= 5 x 20
= 100 km/h

Answer(s): (a) 1040 km; (b) 100km/h