Sean left City X for City W at 07 46. Wendy left City X for City C at the same time. At 11 46, they were 576 km apart. Both maintained a constant speed and reached their destination at the same time at 13 26.
- Find the distance between Cities A and C.
- If Wendy was 57 the speed of Sean, find Sean's speed.
(a)
Time taken for Sean and Wendy to travel 07 46 to 11 46 = 4 h
Time taken for Sean and Wendy to travel 07 46 to 13 26 = 5 h 40 min = 5
4060 h = 5
23 h
Distance travelled by Sean and Wendy in 1 hour
= 576 ÷ 4
= 144 km
Total distance
= 5
23 x 144
= 816 km
(b)
Wendy's distance : Sean's distance
5 : 7
Wendy's speed : Sean's speed
5 : 7
12 u = 144 km
1 u = 144 ÷ 12 = 12 km
Sean's speed
= 7 u
= 7 x 12
= 84 km/h
Answer(s): (a) 816 km; (b) 84km/h