Peter left City B for City A at 08 35. Gem left City B for City C at the same time. At 11 35, they were 585 km apart. Both maintained a constant speed and reached their destination at the same time at 15 15.
- Find the distance between Cities A and C.
- If Gem was 67 the speed of Peter, find Peter's speed.
(a)
Time taken for Peter and Gem to travel 08 35 to 11 35 = 3 h
Time taken for Peter and Gem to travel 08 35 to 15 15 = 6 h 40 min = 6
4060 h = 6
23 h
Distance travelled by Peter and Gem in 1 hour
= 585 ÷ 3
= 195 km
Total distance
= 6
23 x 195
= 1300 km
(b)
Gem's distance : Peter's distance
6 : 7
Gem's speed : Peter's speed
6 : 7
13 u = 195 km
1 u = 195 ÷ 13 = 15 km
Peter's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1300 km; (b) 105km/h