Ben left City Z for City Y at 09 33. Jaslyn left City Z for City C at the same time. At 13 33, they were 528 km apart. Both maintained a constant speed and reached their destination at the same time at 16 13.
- Find the distance between Cities A and C.
- If Jaslyn was 47 the speed of Ben, find Ben's speed.
(a)
Time taken for Ben and Jaslyn to travel 09 33 to 13 33 = 4 h
Time taken for Ben and Jaslyn to travel 09 33 to 16 13 = 6 h 40 min = 6
4060 h = 6
23 h
Distance travelled by Ben and Jaslyn in 1 hour
= 528 ÷ 4
= 132 km
Total distance
= 6
23 x 132
= 880 km
(b)
Jaslyn's distance : Ben's distance
4 : 7
Jaslyn's speed : Ben's speed
4 : 7
11 u = 132 km
1 u = 132 ÷ 11 = 12 km
Ben's speed
= 7 u
= 7 x 12
= 84 km/h
Answer(s): (a) 880 km; (b) 84km/h