Neave left City K for City J at 07 30. Hazel left City K for City C at the same time. At 12 30, they were 700 km apart. Both maintained a constant speed and reached their destination at the same time at 14 21.
- Find the distance between Cities A and C.
- If Hazel was 59 the speed of Neave, find Neave's speed.
(a)
Time taken for Neave and Hazel to travel 07 30 to 12 30 = 5 h
Time taken for Neave and Hazel to travel 07 30 to 14 21 = 6 h 51 min = 6
5160 h = 6
1720 h
Distance travelled by Neave and Hazel in 1 hour
= 700 ÷ 5
= 140 km
Total distance
= 6
1720 x 140
= 959 km
(b)
Hazel's distance : Neave's distance
5 : 9
Hazel's speed : Neave's speed
5 : 9
14 u = 140 km
1 u = 140 ÷ 14 = 10 km
Neave's speed
= 9 u
= 9 x 10
= 90 km/h
Answer(s): (a) 959 km; (b) 90km/h