Albert left City N for City M at 09 21. Ivory left City N for City C at the same time. At 11 21, they were 320 km apart. Both maintained a constant speed and reached their destination at the same time at 15 18.
- Find the distance between Cities A and C.
- If Ivory was 79 the speed of Albert, find Albert's speed.
(a)
Time taken for Albert and Ivory to travel 09 21 to 11 21 = 2 h
Time taken for Albert and Ivory to travel 09 21 to 15 18 = 5 h 57 min = 5
5760 h = 5
1920 h
Distance travelled by Albert and Ivory in 1 hour
= 320 ÷ 2
= 160 km
Total distance
= 5
1920 x 160
= 952 km
(b)
Ivory's distance : Albert's distance
7 : 9
Ivory's speed : Albert's speed
7 : 9
16 u = 160 km
1 u = 160 ÷ 16 = 10 km
Albert's speed
= 9 u
= 9 x 10
= 90 km/h
Answer(s): (a) 952 km; (b) 90km/h