Jenson left City S for City R at 07 45. Gwen left City S for City C at the same time. At 10 45, they were 480 km apart. Both maintained a constant speed and reached their destination at the same time at 14 30.
- Find the distance between Cities A and C.
- If Gwen was 35 the speed of Jenson, find Jenson's speed.
(a)
Time taken for Jenson and Gwen to travel 07 45 to 10 45 = 3 h
Time taken for Jenson and Gwen to travel 07 45 to 14 30 = 6 h 45 min = 6
4560 h = 6
34 h
Distance travelled by Jenson and Gwen in 1 hour
= 480 ÷ 3
= 160 km
Total distance
= 6
34 x 160
= 1080 km
(b)
Gwen's distance : Jenson's distance
3 : 5
Gwen's speed : Jenson's speed
3 : 5
8 u = 160 km
1 u = 160 ÷ 8 = 20 km
Jenson's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1080 km; (b) 100km/h