Sam left City N for City M at 05 48. Jean left City N for City C at the same time. At 10 48, they were 810 km apart. Both maintained a constant speed and reached their destination at the same time at 12 18.
- Find the distance between Cities A and C.
- If Jean was 45 the speed of Sam, find Sam's speed.
(a)
Time taken for Sam and Jean to travel 05 48 to 10 48 = 5 h
Time taken for Sam and Jean to travel 05 48 to 12 18 = 6 h 30 min = 6
3060 h = 6
12 h
Distance travelled by Sam and Jean in 1 hour
= 810 ÷ 5
= 162 km
Total distance
= 6
12 x 162
= 1053 km
(b)
Jean's distance : Sam's distance
4 : 5
Jean's speed : Sam's speed
4 : 5
9 u = 162 km
1 u = 162 ÷ 9 = 18 km
Sam's speed
= 5 u
= 5 x 18
= 90 km/h
Answer(s): (a) 1053 km; (b) 90km/h