Jack left City S for City R at 08 45. Natalie left City S for City C at the same time. At 11 45, they were 612 km apart. Both maintained a constant speed and reached their destination at the same time at 13 40.
- Find the distance between Cities A and C.
- If Natalie was 57 the speed of Jack, find Jack's speed.
(a)
Time taken for Jack and Natalie to travel 08 45 to 11 45 = 3 h
Time taken for Jack and Natalie to travel 08 45 to 13 40 = 4 h 55 min = 4
5560 h = 4
1112 h
Distance travelled by Jack and Natalie in 1 hour
= 612 ÷ 3
= 204 km
Total distance
= 4
1112 x 204
= 1003 km
(b)
Natalie's distance : Jack's distance
5 : 7
Natalie's speed : Jack's speed
5 : 7
12 u = 204 km
1 u = 204 ÷ 12 = 17 km
Jack's speed
= 7 u
= 7 x 17
= 119 km/h
Answer(s): (a) 1003 km; (b) 119km/h