Japheth left City T for City S at 09 38. Yoko left City T for City C at the same time. At 12 38, they were 480 km apart. Both maintained a constant speed and reached their destination at the same time at 16 23.
- Find the distance between Cities A and C.
- If Yoko was 35 the speed of Japheth, find Japheth's speed.
(a)
Time taken for Japheth and Yoko to travel 09 38 to 12 38 = 3 h
Time taken for Japheth and Yoko to travel 09 38 to 16 23 = 6 h 45 min = 6
4560 h = 6
34 h
Distance travelled by Japheth and Yoko in 1 hour
= 480 ÷ 3
= 160 km
Total distance
= 6
34 x 160
= 1080 km
(b)
Yoko's distance : Japheth's distance
3 : 5
Yoko's speed : Japheth's speed
3 : 5
8 u = 160 km
1 u = 160 ÷ 8 = 20 km
Japheth's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1080 km; (b) 100km/h