Ken left City F for City E at 09 37. Natalie left City F for City C at the same time. At 12 37, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 15 23.
- Find the distance between Cities A and C.
- If Natalie was 78 the speed of Ken, find Ken's speed.
(a)
Time taken for Ken and Natalie to travel 09 37 to 12 37 = 3 h
Time taken for Ken and Natalie to travel 09 37 to 15 23 = 5 h 46 min = 5
4660 h = 5
2330 h
Distance travelled by Ken and Natalie in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 5
2330 x 180
= 1038 km
(b)
Natalie's distance : Ken's distance
7 : 8
Natalie's speed : Ken's speed
7 : 8
15 u = 180 km
1 u = 180 ÷ 15 = 12 km
Ken's speed
= 8 u
= 8 x 12
= 96 km/h
Answer(s): (a) 1038 km; (b) 96km/h