Wesley left City P for City N at 07 43. Lucy left City P for City C at the same time. At 10 43, they were 513 km apart. Both maintained a constant speed and reached their destination at the same time at 14 23.
- Find the distance between Cities A and C.
- If Lucy was 45 the speed of Wesley, find Wesley's speed.
(a)
Time taken for Wesley and Lucy to travel 07 43 to 10 43 = 3 h
Time taken for Wesley and Lucy to travel 07 43 to 14 23 = 6 h 40 min = 6
4060 h = 6
23 h
Distance travelled by Wesley and Lucy in 1 hour
= 513 ÷ 3
= 171 km
Total distance
= 6
23 x 171
= 1140 km
(b)
Lucy's distance : Wesley's distance
4 : 5
Lucy's speed : Wesley's speed
4 : 5
9 u = 171 km
1 u = 171 ÷ 9 = 19 km
Wesley's speed
= 5 u
= 5 x 19
= 95 km/h
Answer(s): (a) 1140 km; (b) 95km/h