Wesley left City K for City J at 05 46. Abi left City K for City C at the same time. At 10 46, they were 800 km apart. Both maintained a constant speed and reached their destination at the same time at 12 40.
- Find the distance between Cities A and C.
- If Abi was 35 the speed of Wesley, find Wesley's speed.
(a)
Time taken for Wesley and Abi to travel 05 46 to 10 46 = 5 h
Time taken for Wesley and Abi to travel 05 46 to 12 40 = 6 h 54 min = 6
5460 h = 6
910 h
Distance travelled by Wesley and Abi in 1 hour
= 800 ÷ 5
= 160 km
Total distance
= 6
910 x 160
= 1104 km
(b)
Abi's distance : Wesley's distance
3 : 5
Abi's speed : Wesley's speed
3 : 5
8 u = 160 km
1 u = 160 ÷ 8 = 20 km
Wesley's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1104 km; (b) 100km/h