Jack left City W for City V at 07 43. Jade left City W for City C at the same time. At 11 43, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 13 40.
- Find the distance between Cities A and C.
- If Jade was 45 the speed of Jack, find Jack's speed.
(a)
Time taken for Jack and Jade to travel 07 43 to 11 43 = 4 h
Time taken for Jack and Jade to travel 07 43 to 13 40 = 5 h 57 min = 5
5760 h = 5
1920 h
Distance travelled by Jack and Jade in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 5
1920 x 180
= 1071 km
(b)
Jade's distance : Jack's distance
4 : 5
Jade's speed : Jack's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Jack's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1071 km; (b) 100km/h