Julian left City C for City B at 08 47. Penelope left City C for City C at the same time. At 10 47, they were 408 km apart. Both maintained a constant speed and reached their destination at the same time at 13 37.
- Find the distance between Cities A and C.
- If Penelope was 89 the speed of Julian, find Julian's speed.
(a)
Time taken for Julian and Penelope to travel 08 47 to 10 47 = 2 h
Time taken for Julian and Penelope to travel 08 47 to 13 37 = 4 h 50 min = 4
5060 h = 4
56 h
Distance travelled by Julian and Penelope in 1 hour
= 408 ÷ 2
= 204 km
Total distance
= 4
56 x 204
= 986 km
(b)
Penelope's distance : Julian's distance
8 : 9
Penelope's speed : Julian's speed
8 : 9
17 u = 204 km
1 u = 204 ÷ 17 = 12 km
Julian's speed
= 9 u
= 9 x 12
= 108 km/h
Answer(s): (a) 986 km; (b) 108km/h