Albert left City C for City B at 07 47. Rachel left City C for City C at the same time. At 11 47, they were 672 km apart. Both maintained a constant speed and reached their destination at the same time at 14 37.

1. Find the distance between Cities A and C.
2. If Rachel was ⁵₉ the speed of Albert, find Albert's speed.

(a)
Time taken for Albert and Rachel to travel 07 47 to 11 47 = 4 h
Time taken for Albert and Rachel to travel 07 47 to 14 37 = 6 h 50 min = 6⁵⁰₆₀ h = 6⁵₆ h

Distance travelled by Albert and Rachel in 1 hour
= 672 ÷ 4
= 168 km

Total distance
= 6⁵₆ x 168
= 1148 km

(b)
Rachel's distance : Albert's distance
5 : 9

Rachel's speed : Albert's speed
5 : 9

14 u = 168 km
1 u = 168 ÷ 14 = 12 km

Albert's speed
= 9 u
= 9 x 12
= 108 km/h

Answer(s): (a) 1148 km; (b) 108km/h