Jack left City X for City W at 08 41. Vanessa left City X for City C at the same time. At 12 41, they were 760 km apart. Both maintained a constant speed and reached their destination at the same time at 15 29.
- Find the distance between Cities A and C.
- If Vanessa was 910 the speed of Jack, find Jack's speed.
(a)
Time taken for Jack and Vanessa to travel 08 41 to 12 41 = 4 h
Time taken for Jack and Vanessa to travel 08 41 to 15 29 = 6 h 48 min = 6
4860 h = 6
45 h
Distance travelled by Jack and Vanessa in 1 hour
= 760 ÷ 4
= 190 km
Total distance
= 6
45 x 190
= 1292 km
(b)
Vanessa's distance : Jack's distance
9 : 10
Vanessa's speed : Jack's speed
9 : 10
19 u = 190 km
1 u = 190 ÷ 19 = 10 km
Jack's speed
= 10 u
= 10 x 10
= 100 km/h
Answer(s): (a) 1292 km; (b) 100km/h