David left City A for City Z at 05 27. Mary left City A for City C at the same time. At 10 27, they were 800 km apart. Both maintained a constant speed and reached their destination at the same time at 12 18.
- Find the distance between Cities A and C.
- If Mary was 79 the speed of David, find David's speed.
(a)
Time taken for David and Mary to travel 05 27 to 10 27 = 5 h
Time taken for David and Mary to travel 05 27 to 12 18 = 6 h 51 min = 6
5160 h = 6
1720 h
Distance travelled by David and Mary in 1 hour
= 800 ÷ 5
= 160 km
Total distance
= 6
1720 x 160
= 1096 km
(b)
Mary's distance : David's distance
7 : 9
Mary's speed : David's speed
7 : 9
16 u = 160 km
1 u = 160 ÷ 16 = 10 km
David's speed
= 9 u
= 9 x 10
= 90 km/h
Answer(s): (a) 1096 km; (b) 90km/h