Daniel left City D for City C at 09 47. Marion left City D for City C at the same time. At 12 47, they were 495 km apart. Both maintained a constant speed and reached their destination at the same time at 14 23.

1. Find the distance between Cities A and C.
2. If Marion was ⁴₇ the speed of Daniel, find Daniel's speed.

(a)
Time taken for Daniel and Marion to travel 09 47 to 12 47 = 3 h
Time taken for Daniel and Marion to travel 09 47 to 14 23 = 4 h 36 min = 4³⁶₆₀ h = 4³₅ h

Distance travelled by Daniel and Marion in 1 hour
= 495 ÷ 3
= 165 km

Total distance
= 4³₅ x 165
= 759 km

(b)
Marion's distance : Daniel's distance
4 : 7

Marion's speed : Daniel's speed
4 : 7

11 u = 165 km
1 u = 165 ÷ 11 = 15 km

Daniel's speed
= 7 u
= 7 x 15
= 105 km/h

Answer(s): (a) 759 km; (b) 105km/h