Luke left City X for City W at 08 38. Tiffany left City X for City C at the same time. At 11 38, they were 504 km apart. Both maintained a constant speed and reached their destination at the same time at 15 13.
- Find the distance between Cities A and C.
- If Tiffany was 34 the speed of Luke, find Luke's speed.
(a)
Time taken for Luke and Tiffany to travel 08 38 to 11 38 = 3 h
Time taken for Luke and Tiffany to travel 08 38 to 15 13 = 6 h 35 min = 6
3560 h = 6
712 h
Distance travelled by Luke and Tiffany in 1 hour
= 504 ÷ 3
= 168 km
Total distance
= 6
712 x 168
= 1106 km
(b)
Tiffany's distance : Luke's distance
3 : 4
Tiffany's speed : Luke's speed
3 : 4
7 u = 168 km
1 u = 168 ÷ 7 = 24 km
Luke's speed
= 4 u
= 4 x 24
= 96 km/h
Answer(s): (a) 1106 km; (b) 96km/h