Tom left City U for City T at 09 49. Xylia left City U for City C at the same time. At 11 49, they were 304 km apart. Both maintained a constant speed and reached their destination at the same time at 14 19.
- Find the distance between Cities A and C.
- If Xylia was 35 the speed of Tom, find Tom's speed.
(a)
Time taken for Tom and Xylia to travel 09 49 to 11 49 = 2 h
Time taken for Tom and Xylia to travel 09 49 to 14 19 = 4 h 30 min = 4
3060 h = 4
12 h
Distance travelled by Tom and Xylia in 1 hour
= 304 ÷ 2
= 152 km
Total distance
= 4
12 x 152
= 684 km
(b)
Xylia's distance : Tom's distance
3 : 5
Xylia's speed : Tom's speed
3 : 5
8 u = 152 km
1 u = 152 ÷ 8 = 19 km
Tom's speed
= 5 u
= 5 x 19
= 95 km/h
Answer(s): (a) 684 km; (b) 95km/h