Daniel left City E for City D at 09 32. Tiffany left City E for City C at the same time. At 12 32, they were 594 km apart. Both maintained a constant speed and reached their destination at the same time at 15 12.

1. Find the distance between Cities A and C.
2. If Tiffany was ⁵₆ the speed of Daniel, find Daniel's speed.

(a)
Time taken for Daniel and Tiffany to travel 09 32 to 12 32 = 3 h
Time taken for Daniel and Tiffany to travel 09 32 to 15 12 = 5 h 40 min = 5⁴⁰₆₀ h = 5²₃ h

Distance travelled by Daniel and Tiffany in 1 hour
= 594 ÷ 3
= 198 km

Total distance
= 5²₃ x 198
= 1122 km

(b)
Tiffany's distance : Daniel's distance
5 : 6

Tiffany's speed : Daniel's speed
5 : 6

11 u = 198 km
1 u = 198 ÷ 11 = 18 km

Daniel's speed
= 6 u
= 6 x 18
= 108 km/h

Answer(s): (a) 1122 km; (b) 108km/h