Lee left City X for City W at 09 35. Shiyun left City X for City C at the same time. At 14 35, they were 900 km apart. Both maintained a constant speed and reached their destination at the same time at 16 33.
- Find the distance between Cities A and C.
- If Shiyun was 57 the speed of Lee, find Lee's speed.
(a)
Time taken for Lee and Shiyun to travel 09 35 to 14 35 = 5 h
Time taken for Lee and Shiyun to travel 09 35 to 16 33 = 6 h 58 min = 6
5860 h = 6
2930 h
Distance travelled by Lee and Shiyun in 1 hour
= 900 ÷ 5
= 180 km
Total distance
= 6
2930 x 180
= 1254 km
(b)
Shiyun's distance : Lee's distance
5 : 7
Shiyun's speed : Lee's speed
5 : 7
12 u = 180 km
1 u = 180 ÷ 12 = 15 km
Lee's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1254 km; (b) 105km/h