Tom left City T for City S at 08 47. Tiffany left City T for City C at the same time. At 12 47, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 14 26.
- Find the distance between Cities A and C.
- If Tiffany was 45 the speed of Tom, find Tom's speed.
(a)
Time taken for Tom and Tiffany to travel 08 47 to 12 47 = 4 h
Time taken for Tom and Tiffany to travel 08 47 to 14 26 = 5 h 39 min = 5
3960 h = 5
1320 h
Distance travelled by Tom and Tiffany in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 5
1320 x 180
= 1017 km
(b)
Tiffany's distance : Tom's distance
4 : 5
Tiffany's speed : Tom's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Tom's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1017 km; (b) 100km/h