Oscar left City S for City R at 06 36. Hazel left City S for City C at the same time. At 10 36, they were 672 km apart. Both maintained a constant speed and reached their destination at the same time at 13 11.
- Find the distance between Cities A and C.
- If Hazel was 57 the speed of Oscar, find Oscar's speed.
(a)
Time taken for Oscar and Hazel to travel 06 36 to 10 36 = 4 h
Time taken for Oscar and Hazel to travel 06 36 to 13 11 = 6 h 35 min = 6
3560 h = 6
712 h
Distance travelled by Oscar and Hazel in 1 hour
= 672 ÷ 4
= 168 km
Total distance
= 6
712 x 168
= 1106 km
(b)
Hazel's distance : Oscar's distance
5 : 7
Hazel's speed : Oscar's speed
5 : 7
12 u = 168 km
1 u = 168 ÷ 12 = 14 km
Oscar's speed
= 7 u
= 7 x 14
= 98 km/h
Answer(s): (a) 1106 km; (b) 98km/h