Peter left City H for City G at 07 31. Winnie left City H for City C at the same time. At 10 31, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 13 28.
- Find the distance between Cities A and C.
- If Winnie was 45 the speed of Peter, find Peter's speed.
(a)
Time taken for Peter and Winnie to travel 07 31 to 10 31 = 3 h
Time taken for Peter and Winnie to travel 07 31 to 13 28 = 5 h 57 min = 5
5760 h = 5
1920 h
Distance travelled by Peter and Winnie in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 5
1920 x 180
= 1071 km
(b)
Winnie's distance : Peter's distance
4 : 5
Winnie's speed : Peter's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Peter's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1071 km; (b) 100km/h