Howard left City G for City F at 07 32. Cathy left City G for City C at the same time. At 12 32, they were 825 km apart. Both maintained a constant speed and reached their destination at the same time at 14 24.
- Find the distance between Cities A and C.
- If Cathy was 56 the speed of Howard, find Howard's speed.
(a)
Time taken for Howard and Cathy to travel 07 32 to 12 32 = 5 h
Time taken for Howard and Cathy to travel 07 32 to 14 24 = 6 h 52 min = 6
5260 h = 6
1315 h
Distance travelled by Howard and Cathy in 1 hour
= 825 ÷ 5
= 165 km
Total distance
= 6
1315 x 165
= 1133 km
(b)
Cathy's distance : Howard's distance
5 : 6
Cathy's speed : Howard's speed
5 : 6
11 u = 165 km
1 u = 165 ÷ 11 = 15 km
Howard's speed
= 6 u
= 6 x 15
= 90 km/h
Answer(s): (a) 1133 km; (b) 90km/h