Elijah left City R for City Q at 09 23. Mary left City R for City C at the same time. At 12 23, they were 495 km apart. Both maintained a constant speed and reached their destination at the same time at 16 15.
- Find the distance between Cities A and C.
- If Mary was 56 the speed of Elijah, find Elijah's speed.
(a)
Time taken for Elijah and Mary to travel 09 23 to 12 23 = 3 h
Time taken for Elijah and Mary to travel 09 23 to 16 15 = 6 h 52 min = 6
5260 h = 6
1315 h
Distance travelled by Elijah and Mary in 1 hour
= 495 ÷ 3
= 165 km
Total distance
= 6
1315 x 165
= 1133 km
(b)
Mary's distance : Elijah's distance
5 : 6
Mary's speed : Elijah's speed
5 : 6
11 u = 165 km
1 u = 165 ÷ 11 = 15 km
Elijah's speed
= 6 u
= 6 x 15
= 90 km/h
Answer(s): (a) 1133 km; (b) 90km/h