Caden left City M for City L at 07 38. Eva left City M for City C at the same time. At 10 38, they were 612 km apart. Both maintained a constant speed and reached their destination at the same time at 13 33.
- Find the distance between Cities A and C.
- If Eva was 57 the speed of Caden, find Caden's speed.
(a)
Time taken for Caden and Eva to travel 07 38 to 10 38 = 3 h
Time taken for Caden and Eva to travel 07 38 to 13 33 = 5 h 55 min = 5
5560 h = 5
1112 h
Distance travelled by Caden and Eva in 1 hour
= 612 ÷ 3
= 204 km
Total distance
= 5
1112 x 204
= 1207 km
(b)
Eva's distance : Caden's distance
5 : 7
Eva's speed : Caden's speed
5 : 7
12 u = 204 km
1 u = 204 ÷ 12 = 17 km
Caden's speed
= 7 u
= 7 x 17
= 119 km/h
Answer(s): (a) 1207 km; (b) 119km/h