Xavier left City Q for City P at 07 30. Lynn left City Q for City C at the same time. At 10 30, they were 594 km apart. Both maintained a constant speed and reached their destination at the same time at 12 20.
- Find the distance between Cities A and C.
- If Lynn was 56 the speed of Xavier, find Xavier's speed.
(a)
Time taken for Xavier and Lynn to travel 07 30 to 10 30 = 3 h
Time taken for Xavier and Lynn to travel 07 30 to 12 20 = 4 h 50 min = 4
5060 h = 4
56 h
Distance travelled by Xavier and Lynn in 1 hour
= 594 ÷ 3
= 198 km
Total distance
= 4
56 x 198
= 957 km
(b)
Lynn's distance : Xavier's distance
5 : 6
Lynn's speed : Xavier's speed
5 : 6
11 u = 198 km
1 u = 198 ÷ 11 = 18 km
Xavier's speed
= 6 u
= 6 x 18
= 108 km/h
Answer(s): (a) 957 km; (b) 108km/h